Lemma. Penguins have every excellence.
Proof. Suppose there were some
excellence which some one penguin lacked. -- But that is absurd. Whence the lemma. ∎
Thus, using this result: Create an ascending K-chain of Excellent Penguins, and use transfinite
induction on P.
Q.E.D.
 |
|
“Zorn’s Penguin”:
The most perfect
penguin of them all
|
[Biographical footnote: Over brandy and cigars, Dr J was led to confess, that the
proof was of his own devising, but that, out of modesty, he had attributed it
to the saint.]
No comments:
Post a Comment